Inverse Sine Function
Range:
On this interval, y=arcsin x.
Evaluating the Inverse Sine Function
For this problem we would find an angle whose sine is equal to -1/2.
on the interval
So we get:
Inverse Cosine Function
Range:
On this interval, y=arccos x.
For this problem, we need to find an angle whose cosine equals:
, so
Inverse Properties
sin(arcsin x )= x and arcsin(siny) = y when
and
cos(arccos x) = x and arccos(cosy) = y when
and
tan(arctan x) = x and arctan(tan y) = y when
x is a real number and
-5 lies on the domain of arctan x, so we can use the inverse property, and we get:
No comments:
Post a Comment