Sunday, November 11, 2012

Inverse Functions

Inverse Sine Function


Range:

On this interval, y=arcsin x.


Evaluating the Inverse Sine Function







                                    
For this problem we would find an angle whose sine is equal to -1/2.





on the interval 




So we get:



Inverse Cosine Function



                                    Range: 

On this interval, y=arccos x. 





For this problem, we need to find an angle whose cosine equals: 
,  so


Inverse Properties

sin(arcsin x )= x  and arcsin(siny) = y when


   and


cos(arccos x) = x and arccos(cosy) = y when 


and 


tan(arctan x) = x and arctan(tan y) = y  when

x is a real number and 




-5 lies on the domain of arctan x, so we can use the inverse property, and we get:




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